Question

in the given figure ABCD is a square find the value of x​

Answer 1

Thus, The value of $x$ is $42.5degree$

Step-by-step explanation:

Given;

$ABCD$ is a square.

For an square, Two diagonal are make equal right angle and also make equal angle at every corner point.

So from figure;

$\angle AOB=\angle BOC=\angle COD=\angle AOD=85degree$

And from $\bigtriangleup AOD$,

$\angle DAO=\angle ADO=x$

In triangle, sum of all three angle equal to $180degree$

So,

$\angle DAO+\angle ADO+\angle AOD=180$

⇒$x+x+85=180$

⇒$2x=180-85$

⇒$x=\frac{95}{2}$

∴$x=42.5$

∴ The value of $x$ is $42.5degree$