Question

In the given figure, ABCD is a square with diagonal 44 cm. How much paper of each shade is needed to make a kite given in the figure?

Answer 1

Thank you for asking this question. Here is your answer:

(BC)² + (BC)² = (DB)²

a² + a² = (44)²

2a² = 44 x 44

a² = 44x44/2

a² = 11 x 2 x 4 x 11

a² = 11 x 11 x 2 x 2 x 2

a = 11 x 2 √2

Area = a x a

= 44 x 22

Area = 968

If there is any confusion please leave a comment below.

Answer 2

Solution:

All the sides of a square are equal and all the angle are right angle.

let side of square is a cm

We know that area of square is
${a}^{2} \: {cm}^{2}$
To find the area of ABCD

Apply Pythagoras Theorem in ∆DAB

${DB}^{2} = {DA}^{2} + {AB}^{2} \\ \\ 44 \times 44 = {a}^{2} + {a}^{2} \\ \\ 2 {a}^{2} = 1936 \\ \\ {a}^{2} = \frac{1936}{2} \\ \\ {a}^{2} = 968 \: {cm}^{2}$

So,the paper to be used to make that kite is 968 sq-cm.

* No figure attached in the question,to calculate the area of coloured paper.

Hope it helps you.