In the given figure ABCD is a trapezium and AB||CD. Find the values of x.
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Answered by
50
triangle ADO and BCO are similar hence,
AO/OC=BO/OD
(x-2)/(x-1)=(x+3)/(x+5)
-3x+2=8x+15
11x=-13
x=-13/11
Hope it helped.
AO/OC=BO/OD
(x-2)/(x-1)=(x+3)/(x+5)
-3x+2=8x+15
11x=-13
x=-13/11
Hope it helped.
rakshankmr:
It really helped^_^ thanks a lot "sky"... :P
wait a sec....how are they similar?
there are vertically opp angles and ?
Angles, AOD and BOC are equal. so to DAC & ACB , and ADO & OBC. and just because all of the three angles are equal, we can say that those both triangles are similar I hope that your doubt is cleared, you can always ask if you have any. ^^
Ok I get it! Thanks for clearing my doubt!
You're most welcome. ^^
Answered by
13
Hence the wo triangles are similar,
(x-2)/(x-1)=(x+3)/(x+5)
means, x=-13/11
(x-2)/(x-1)=(x+3)/(x+5)
means, x=-13/11
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