in the given figure ABCD is a trapezium find the values of X Y and Z
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Here,
angle y=180-100 =80° (linear pair angles)
angle x =100° (alternate interior angle)
angle z = 360- angle A+ angle B +angle C ( sum of all angles of a quadrilateral =360°)
Z= 360-120+100+80
Z=360-300
Z=60
Hence, x=100° ,y=80°,z=80°
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