Question

In the given figure ABCD is a trapezium in which
AB = 40m,BC = 15m,CD = 28m, AD = 9m and CELAB. Area of trap.
ABCD is​

Answer 1

${\huge{\boxed{\mathbb{\blue{‡ANSWER:-}}}}}$

IN THE FIG.

CE ⊥ AB

CE || AD

THIS SHOWS THAT

AD = 9cm = CE = 9cm

So , Now , Area of Trapezium :-

Formula :-

1/2 × sum of || sides × distance b/w || sides

$\frac{1}{2} \times (ab + dc) \times ce \\ \\ \frac{1}{2} \times( 40 + 28) \times 9 \\ \\ \\ \frac{1}{2} \times 68 \times 9 \\ \\ = 306 \: {m}^{2}$

HOPE IT HELPS

MARK BRAINLIEST PLS