in the given figure, ABCD is a trapezium in which AB || DC and E is the mid-point of AD. A line segment EF which is parallel AB intersects BC at F. Shiw that F is the mid-point of BC.
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Join DB now in triangle ABD
E is midpoint of AD and is parallel to AB so by converse of midmoint theorem,line from E bisect BD at Q.Now in triangle DBC, Q is midpoint of DB and is parallel to CD so by converse of midpoint theorem
Line from Q bisect BC at F .so f is midpoint of BC
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