Question

in the given figure abcd is a trapezium with Ab parallel to dc . the bicetor of angle B and angle C meet at one point. Find angle BOC​

Answer 1

Answer:

In the given figure

b+c = 180

1/2×b + 1/2×c = 180/2= 90

b/2 + c/2 = 90

angle1 + angle2= 90

In ∆ BOC

angle1 + angle2 + BOC = 180

90+BOC = 180

∆ BOC = 180 - 90

∆ BOC = 90

Answer 2

Step-by-step explanation:

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