Question

in the given figure ABCD is a triangle with length p square to q -5 and breadth q square + 40 find the area of shaded triangle p a b​

Answer 1

Diagonal of rectangle

Half the area of rectangle

Height = 12 = CP

Length BP

Area of shaded region

Answer 2

$area \: ofa \: \: apb \: = \frac{1}{2} \times l \times b$

$= \frac{1}{2} \times ( {p}^{2} q - 5)( {q}^{2} + 40)$

$= \frac{1}{2} \times {p}^{2}q( {q}^{2} + 40) - 5( {q}^{2} + 40)$

$= \frac{1}{2} \times {p}^{2} {q}^{3} + 40 {p}^{2}q \: - 5 {q}^{2} - 200$

$p = {q}^{2} \: \: = a = 40 {q}^{2} \: = b = 200$