Question

In the given figure ,ABCD is cyclic quadrilateral
ZDAB =60°, then ZDCE is:
(а) 60°
(b) 90°
(c) 120°
(d) 140°

​

Answer 1

Step-by-step explanation:

BOD=160

∘

But ∠BAD=

2

1

∠BOD

∠BAD=

2

1

×160

∘

=80

∘

Since ABCD is a cyclic quadrilateral

∴∠BAD+∠BCD=180

∘

[∴ opposite ∠s of a cyclic quadrilateral are supplementary]

⇒80

∘

+∠BCD=180

∘

⇒∠BCD=180

∘

−80

∘

=100

∘

FOLLOW ME