In the given figure ,ABCD is cyclic quadrilateral
ZDAB =60°, then ZDCE is:
(а) 60°
(b) 90°
(c) 120°
(d) 140°
Answers
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Step-by-step explanation:
BOD=160
∘
But ∠BAD=
2
1
∠BOD
∠BAD=
2
1
×160
∘
=80
∘
Since ABCD is a cyclic quadrilateral
∴∠BAD+∠BCD=180
∘
[∴ opposite ∠s of a cyclic quadrilateral are supplementary]
⇒80
∘
+∠BCD=180
∘
⇒∠BCD=180
∘
−80
∘
=100
∘
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