In the given figure ABCD is rhombus with diagonals AC = 16 cm and BD = 8 cm. Find the coordinates of
A, B, C and D.
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Given: ABCD is rhombus with diagonals AC = 16 cm and BD = 8 cm.
To find: The coordinates of A, B, C and D.
Solution:
- Now we have given that AC = 16 cm.
- We also know that the diagonals of rhombus bisect each other. So:
AC = AO + OC
Here AO = OC.
AC = 2(AO)
16 cm/ 2 = AO
AO = 8 cm = OC.
- Since A and C are 8 cm apart from origin, so :
- A = (-8,0) as the point is on x axis and 8 cm to the left of origin.
- C = (8,0) as the point is on x axis and 8 cm to the right of origin.
- Similarly:
BD = BO + OD
Here OB = OD
BD = 2(OB)
8 cm / 2 = OB
4 cm = OB = OD
- Since B and D are 4 cm apart from origin, so :
- B = (0,4) as the point is on y axis and 4 cm to the above of origin.
- D = (0,-4) as the point is on y axis and 4 cm to the below of origin.
Answer:
So the coordinates are: A = (-8,0), B = (0,4), C = (8,0), D = (0,-4)
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