in the given figure ,ABCD ,is strap with AB parallel to DC and angle ABC= 90 .BCEF is a quadrilateral of a circle .If BC=CD=4.2 cm and AE = 1.8 cm ,find the area of the shaded region........
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Answer:⤵️
7.56 cm^2
Step-by-step explanation:⤵️
in fig.
given,
AE= 1.8 cm
BC = DC = 4.2cm
in fig,
radius of circle = BC= 4.2cm
then,
AB= AE + radius of circle
=> 1.8 +4.2
=> 6cm
then,
ABCD is trapezium,
area of ABCD
= 1/2×(AB+DC)×BC
= 1/2×(6+4.2)×4.2
= 21.42 cm^2
then,
area of BCE quadrilateral of a circle
= 1/4×πr^2
= 1/4×π×4.2×4.2
= 1/4×22/7×17.64
= 13.86cm^2
then,
area of the shaded region
=21.42-13.86
=7.56 cm^2
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