In the given figure , ABCD isa rhombus .Diagonals AC and BD intersect at O .<ABO 54
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angle OAB =55°
angle DAB = 55*2=110° [diagonals of rhombus bisect the vertex angles]
angle DAB = angle DAB =110° [properties of a parallelogram as rhombus is a parallelogram]
angle ABC = 180- angle DAB= 180-110=70°
Angle ADC= angle ABC =70°
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