Question

In the given figure, ABCDEF is a regular hexagon of side 12 cm. P, Q and R are the mid points of the sides AB, CD and EF respectively. What is the area (in sq.cm) of triangle PQR?

A) 27√6 B) 81√3 C) 54√3 D) 54√6

Answer 1

Answer:

First we have to find the side of the triangle to calculate the area.

Step-by-step explanation:

EDFC is a trapezium.

Largest diagonal of regular hexagon is always double the size of the side.

FC = 24  

Now RQ is connected through mid point so,

$RQ = \frac{24*1 + 12*1 }{2} \\RQ = 18$

So now we can find the area of the triangle by the formula of equilateral traiangle.

$= \sqrt{3} / 4 * 18^{2} \\= 81 \sqrt{3}$