Question

In the given figure above,AB||DE and AC||DF, prove that angleBAC=angleEDF.​

Answer 1

Answer:

Const : join the line BC and EF

In triangle BAC and EDF

AB = DE (AB parallel DE)

AC = DF ( AC parallel DF)

angle1 = angle2 (angle A = angle D)

Triangle BAC ~ triangle EDF (by SAS)

angle BAC = angle EDF(By C. P. C. T)

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