Question

in the given figure Abparllel CD, BCparllelDE then find the values of x, y​

Answer 1

Step-by-step explanation:

ANSWER

Given that AB∣∣CD

Taking BC as transversal,

∠ABC=∠BCD (alternate interior angles)

3x=105

∘

x=35

∘

Also, given that BC∣∣DE.

Taking CD as transversal,

∠CDE=∠BCD=105

∘

(alternate interior angles)

Now applying angle sum property in triangle CDE,

∠CDE+∠DEC+∠DCE=180

∘

105

∘

+y+24

∘

=180

∘

y=51

∘

Answer 2

Answer: UR REQUIRED ANSWER ;-

given , AB ║ CD

SO, 20° + y = 58 ° ....... [ corresponding angles ]

⇒ y = 58° - 20° = 38 °

Now, In Δ PQR

⇒ x + y+ 100° = 180° ......... [ angle sum property of Δ]

⇒ x + 38 ° + 100 ° = 180°

⇒ x = 42 ° .

Step-by-step explanation: hope this will help u mate , need feedback plz

itz akansha .

Dark Queen ...