Question

In the given figure ac=ae ab=ad and angle bad =angle eac show that bc=de

Answer 1

This is your Answer

Hope it helps you!

Answer 2

GIVEN:-

AC = AE

AB= AD

$\large\sf{\angle{BAD}=\angle{EAC}}$

TO PROVE:-

BC = DE

PROOF:-

$\large\sf{\angle{BAD}=\angle{EAC}}$

$\large\sf{\angle{BAD}+\angle{DAC}=\angle{EAC}+\angle{DAC}}$

$\large\sf{\angle{BAC}=\angle{EAD}}$..........(1)

⠀⠀

$\large\sf\red{Now\:on\:∆ABC\:and\:AED}$

$\large\sf{AC=AE(given)}$

$\large\sf{\angle{BAC}=\angle{EAD}(from(1))}$

$\large\sf{AB=AD(given)}$

$\therefore$By SAS congruence rule,

$\large\sf{∆ABC\:\cong\:∆AED}$

$\large\sf{BC=DE(CPCT)}$