Question

in the given figure AC and BD are common tangent to the circle of unequal radius prove that AC equal to BD​

Answer 1

Answer:

Just draw another tangent AD.

Now, consider tangents ADandDC.

Since, the lengths of tangents from an external point to a circle is equal

AD=CD−−−−(i)

Similarly

AD=AB−−−−−(ii)

Now, From (i) and (ii) we get

AB=CD

Proved.

Hope you are satisfied