In the given figure AC = CE =3 cm and BC = DC = 2 cm Prove that ∆ABC = ∆EDC.
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Answer:
DE
AB
=
DC
BC
=
CE
AC
3
4
=
4.8
BC
=
4.2
AC
⇒ BC=6.4 and AC=5.6
Hence CA=5.6cm,DA=6.4cm
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