In the given figure AC, CE, &EH are tangents drawn to a circle at B, D, & F respectively. If CB=5cm & EF=3cm, then the length of CE is____
Answers
Answered by
9
Answer:
8 cm
Step-by-step explanation:
As CB=CD , ∴CD=5 cm
Similarly, EF=DE , ∴DE =3 cm
now, CE= CD+DE
= 5+3 cm
= 8 cm
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Answered by
1
Answer:
CB =CD ,so CD =5
and de=3cm
ce=cd+de
5+3=8
so the correct answer is 8
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