Question

in the given figure AC = DC and CB = CE. show that AB = DE ​

Answer 1

HIIIIII..

We have AC = DC ...(1) [Given]

And CB • CE...(2) [Given]

Now, by axiom 2, if equals are added to equals, the wholes are equal.

Adding (1) and (2).

we get AC + CB = DC + CE

Hence, AB = DE

HOPE IT HELPS YOU....

PLEASE MARK ME BRAINLIST

Answer 2

ʕ•ﻌ•ʔ$\huge\bold\pink{hello!!!}$ʕ•ﻌ•ʔ

HERE IS UR ANSWER

_____________________

refer attachment^^