in the given figure AC=DC and CB=CE,then prove that AB=DE and write the axiom used also
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Answered by
22
Take the two triangles. Prove them congruent. And side AB=DE
Answered by
63
in this figure this parallogram ABED.which meet at point c.
proof =>in ∆ACD andECB
AC=DC (given)
CB=CE (given)
<ACD=ECB (vertically opposite angle)
so ∆ACD~=∆ECD by SAS congruent
AB=DE by (cpct)
and I think axiom 5
proof =>in ∆ACD andECB
AC=DC (given)
CB=CE (given)
<ACD=ECB (vertically opposite angle)
so ∆ACD~=∆ECD by SAS congruent
AB=DE by (cpct)
and I think axiom 5
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