In the given figure, AC=DC, CB=CE. Show that AB=DE.Write the Euclid's axiom to support this.
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Answered by
130
when aquals r added to equals , the wholes are equals
(AC+CD=CE+CB)
(AC+CD=CE+CB)
ishita23:
Can you explain?
Answered by
104
In triangle ACD ,
AC = DC ( Given ) ---------(1)
and...
In triangle ECB ,
CB = CE ( Given ) ---------(2)
When we add (1) and (2)
AC+CB = DC+CE
AB = DC
THIS is only possible due to the AXIOM - 2
( IF EQUALS ARE ADDED TO EQUALS THE WHOLE ARE EQUAL )
MAY MY ANSWER HELP YOU
^_^ ^_^
AC = DC ( Given ) ---------(1)
and...
In triangle ECB ,
CB = CE ( Given ) ---------(2)
When we add (1) and (2)
AC+CB = DC+CE
AB = DC
THIS is only possible due to the AXIOM - 2
( IF EQUALS ARE ADDED TO EQUALS THE WHOLE ARE EQUAL )
MAY MY ANSWER HELP YOU
^_^ ^_^
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