. In the given figure, AC > AB and D is a point on
AC such that AB = AD. Prove that (i) CD <BC.
(ii) AC-AB < BC.
A
Answers
Answered by
0
Step-by-step explanation:
In ∆ ABD, it is given that AB = AD …
.(i) In ∆ ABC, AB + BC > AC
=> AB + BC > AD + CD
=> AB + BC > AB + CD [∵AD = AB]
=> BC > CD
Similar questions