Question

. In the given figure, AC > AB and D is a point on
AC such that AB = AD. Prove that (i) CD <BC.
(ii) AC-AB < BC.
A​

Answer 1

Step-by-step explanation:

In ∆ ABD, it is given that AB = AD …

.(i) In ∆ ABC, AB + BC > AC

=> AB + BC > AD + CD

=> AB + BC > AB + CD [∵AD = AB]

=> BC > CD