Question

In the given figure ,AC> AB and D is a point on AC such that AD=AB. Show that BC > CD.​

Answer 1

Step-by-step explanation:

Given an isosceles triangle △ABC,

∴AB=AC

Also, BE=CD

We have to prove that AD=AE

Since, AB=AC

∴∠C=∠B [Angles opposite to equal sides are equal] .... (1)

In △ACD and △ABE,

AC=AB (Given)

∠C=∠B (From (1))

CD=BE (Given)

So, △ACD≅△ABE{ SAS congruence rule}

∴AD=AE{ By CPCT}

Hence proved.

solution