Question

In the given figure, AC is a straight line. Find : x, (ii) <AOB, (iii) <BOC.
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Answer 1

Answer:

We know that

∠AOB and ∠COB are linear pairs.

It can be written as

∠AOB+∠COB=180

0

Substituting the values

x+25

0

+3x+15

0

=180

0

By further calculation

4x+40

0

=180

0

So we get

4x=180−40=140

0

(i) x=140/4=35

0

(ii) ∠AOB=x+25

Substituting the value of x

∠AOB=25+35=60

0

(iii) ∠BOC=3x+15

0

Substituting the value of x

∠BOC=(3×35)+15

∠BOC=120

0