In the given figure, AC is the bisector of mezor angle DAB.If mezor angle DAB=80° and mezor angle =70° ,find mezor angle ADC
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if I'm not wrong then angle ADC will be 105 hope it is correct nd will help you
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∠ADC = 105°
Given:
∠DAB = 80°
∠DCB = 70°
AC is the bisector of ∠ADC and ∠DCB
We have to find ∠ADC
Now, since AC is the angle bisector of ∠ADC and ∠DCB
Hence, AC divide the ∠ADC and ∠DCB in equal parts
⇒∠DAC= ∠DAB/2 = 80°/2
⇒ ∠DAC= 40°
⇒ ∠DCA= ∠DACB/2 = 70°/2
⇒ ∠DCA= 35°
Now, accorsing to the traingle property,
∠DCA + ∠DAC + ∠ADC = 180°
40° + 35° + ∠ADC = 180°
∠ADC = 180° - 75°
∠ADC = 105°
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