In the given figure, ∆ACB ∼ ∆APQ. If BC = 8 cm, PQ = 4 cm, BA = 6.5 cm and AP = 2.8 cm, find CA and AQ.
Answers
SOLUTION :
Given : ΔACB∼ΔAPQ , BC = 8 cm, PQ = 4 cm, BA = 6.5 cm, and AP = 2.8 cm
ΔACB∼ΔAPQ
BA/AQ = CA/AP = BC/PQ
[Since, triangles are similar , hence corresponding sides will be proportional]
Therefore, 6.5/AQ = 8/4
AQ = (6.5x4)/8
AQ = 6.5/2
AQ = 3.25 cm
Similarly, CA/AP = BC/PQ
CA/2.8 = 8/4
CA = 2.8 x 2
CA = 5.6 cm
Hence, CA = 5.6 cm and AQ = 3.25 cm.
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Answer:
Given : ΔACB∼ΔAPQ , BC = 8 cm, PQ = 4 cm, BA = 6.5 cm, and AP = 2.8 cm
ΔACB∼ΔAPQ
BA/AQ = CA/AP = BC/PQ
[Since, triangles are similar , hence corresponding sides will be proportional]
Therefore, 6.5/AQ = 8/4
AQ = (6.5x4)/8
AQ = 6.5/2
AQ = 3.25 cm
Similarly, CA/AP = BC/PQ
CA/2.8 = 8/4
CA = 2.8 x 2
CA = 5.6 cm
Hence, CA = 5.6 cm and AQ = 3.25 cm.
(OR)
Given,
ΔACB ∼ ΔAPQ
BC = 8 cm, PQ = 4 cm, BA = 6.5 cm and AP = 2.8 cm
Required to find: CA and AQ
We know that,
ΔACB ∼ ΔAPQ [given]
BA/ AQ = CA/ AP = BC/ PQ [Corresponding Parts of Similar Triangles]
So,
6.5/ AQ = 8/ 4
AQ = (6.5 x 4)/ 8
AQ = 3.25 cm
Similarly, as
CA/ AP = BC/ PQ
CA/ 2.8 = 8/ 4
CA = 2.8 x 2
CA = 5.6 cm
Hence, CA = 5.6 cm and AQ = 3.25 cm.
Step-by-step explanation: