In the given figure, acb is the diameter of the circle and p is any point on the circle. the measure of ∠apb is
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1
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Answer will be 90⁰
There is theorem that if the triangle is between a a semicircle than angle of triangle opposite to diameter will be 90⁰
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0
Answer:
90°
Explanation of the question.
Given:
1).ACB is a diameter of radius 'R'.
2). 'P' is any point on circle.
Therefore arc APB forms a semicircle and angle APB is inscribed in it.
As we know that any angle inscribed in a semicircle measures 90°.
Thus angle APB measures 90°
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