Question

In the given figure, ∠ACP = 40° and ∠BPD = 120°, then find ∠CBD .​

Answer 1

Answer:

BPD = ∠ACP = 40° [angle in same segment]

Now, in △BPD, we have

∠PBD + ∠BPD + ∠BDP = 180°

⇒ ∠PBD + 120° + 40° = 180°

⇒ ∠PBD = 180° - 160° = 20°

or ∠CBD = 20