In the given figure, AD = 24 cm, AP = 36 cm, and BC = 10 cm.
B
What is the length of BQ?
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AP = AQ , BP = PR and CR = CQ (tangents from an external point)
Perimeter of ∆ABC = AB + BR + RC + CA
= AB + BP + CQ + CA
= AP + AQ
= 2AP
∆APO is a right-angled triangle. AO2 = AP2 + PO2
132 = AP2 + 52
AP2 = 144
AP = 12
∴ Perimeter of ∆ABC = 24 cm
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