Question

In the given figure,AD=AE,BD=EC.prove that angle abc is isosceles Triangle

Answer 1

To prove that ABC is an isosceles triangle,

We should prove that AB=AC

In ΔABD and ΔAEC ,

• AD=AE
• BD=EC

As AD=AE , ∠ADE=∠AED

∴ 180°-∠ADE=180°-∠AED

• ∴ ∠ADE=∠AEC

By SAS criterion, ΔABD≅ΔACE

By CPCT, AB=AC

Hence ΔABC is an isosceles triangles.

  HOPE IT HELPS !