Question

In the given figure, AD and CF are the medians of ∆ABC intersect at G. The length of GD can be equal to

Answer 1

Answer:

GD=$\sqrt{61}$CM MARK IT AS BRAINLIEST.

Step-by-step explanation:

In right angled tri. GDC:-

GC=6cm

CD=5cm

therefore, GD^2=GC^2+CD^2

GD^2=6^2+5^2

GD^2=36+25

GD^2=61

GD=$\sqrt{61}$CM

Answer 2

Answer:

please go through the picture