Question

In the given figure, AD = BC, AC = BD.
Prove that ΔADC = ΔBCD.

Answer 1

Answer:

In triangles ABD and BAC, we have

AD=BC   (given);

AB=AB   (common);

AC=BD   (given).

We can use SSS condition to conclude that △ABD≅△BAC. From this we conclude that

∠ADB=∠BCA and ∠DAB=∠CBA.