Question

in the given figure AD=BC, AC=BD Prove that angle ADB=angle ACB​

Answer 1

Answer:

In triangles ABD and BAC, we have

AD=BC (given);

AB=AB (common);

AC=BD (given).

We can use SSS condition to conclude that △ABD≅△BAC. From this we conclude that

∠ADB=∠BCA and ∠DAB=∠CBA.

Step-by-step explanation:

we get all of them equal at last because of c.p.c.t (corresponding sides of congruent triangle)

hope it helps .

Answer 2

Step-by-step explanation:

In triangles ABD and BAC, we have

AD=BC (given);

AB=AB (common);

AC=BD (given).

△ABD≅△BAC. [SSS Congruency]

Therefore , ∠ADB=∠ACB [By CPCT]

Hope it helps ....,..