In the given figure, AD = BC and AC = BD. Prove
that angle
ADC = angle BCD
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In ∆ADC and ∆BCD,
AD = BC (given)
AC = BD (given)
DC = CD (common)
by SSS congruency rule
∆ADC ≅ ∆BCD
by cpct :-
<ADC = <BCD
hence proved !
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