Question

In the given figure AD=BC and angle ADC = angle BCD.
Prove that AC =BD

Answer 1

I hope this help ful for you

Answer 2

according to figure,

AD = BC and angle ADC = angle BCD

we have to prove AC = BD

let's see ∆ADC and ∆BCD

AD = BC [ given ]

angle ADC = angle BCD [ given ]

CD = CD

from S - A - S

∆ADC congruence ∆BCD

and we know, two triangles are congruence means both are identical in shape and size.

so, AC = BD [hence proved ]

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