Question

in the given figure, AD - BC - Som AB - 4.com, CD - 10 cm. What is the length of CF if B is the midpoint of ED and EF DF? B​

Answer 1

Answer:

Given: D and E are mid points of BC and AB respectively. DF∥CE

In △BEC,

FD∥CE and D is mid point of BC

Hence, by converse of mid point theorem, F is mid point of BE.

Hence, FB=

2

1

(BE)

FB=

2

1

(

2

1

AB) (E is mid point of AB)

FB=

4

1

Step-by-step explanation:

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