Question

In the given figure, AD, BE and CF are three medians of triangle ABC
Prove that 3(AB + BC + CA) > 2 (AD + BE + CF)​
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Answer 1

Answer:

It has been proved that perimeter is greater than sum of its three medians.

Answer 2

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Step-by-step explanation:

In the given figure, AD, BE and CF are three medians of triangle ABC

Prove that 3(AB + BC + CA) > 2 (AD + BE + CF)

Use Congruence

Then use Sum of 2 sides is greater than twice the median