Question

In the given figure, AD bisects /A, DE | CA and DF | AB. Prove that

i. △AFD ≅ △AED

ii. AF = AE​

Answer 1

Answer:

BD=CD

Step-by-step explanation:

If D is a point on the side BC of a ΔABC such that AD bisects ∠BAC. Then,

(a) BD = CD

(b) BA > BD

(c) BD > BA

(d) CD > CA

Thinking Process

(i) Firstly, use the property, exterior angle of a triangle is greater than interior opposite

angle.

(ii) Secondly, use the property that in a triangle, the side opposite to the greater angle is longer.