in the given figure, AD bisects angle BAC and AD bisects BC. Show that triangle ABC is an isoscele triangle
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Step-by-step explanation:
In ∆ADB & ∆ADC
AD=AD[common]
BD=BC[AD perpendicular to BC]
angle ADB= angle ADC[each 90°]
therefore, ∆ADB congruent to ∆ ADC[
SAS rule of congruency]
AB=AC[c.p.c.t.]
therefore , ∆ ABC is an isosceles triangle.
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