Question

In the given figure, AD = BP ,P and Q are the mid points of the sides AB and DR respectively. If PR ║BS, prove that (i) AC║BS (ii) DS = 3DQ.

Answer 1

Answer:

Correct option is

D

AQ2+CP2=45AC2

AQ2=AB2+BQ2

since Q is midpoint on BC, BQ=2BC

AQ2=AB2+(2BC)2

         =AB2+4BC2 ...(i)

Similarly CP2=BC2+BP2

since P is midpoint on AB, BP=2AB

CP2=BC2+(2AB)2 

       =4AB2+BC2 ...(ii)

∴AQ2+CP2=AB2+4