Question

In the given figure, AD = DC. Find

(a) cos x

(b) sin^2 x – cos^2x

(c) sin^2y+cos^2y​

Answer 1

Answer:

sorry I m unable to solve it right now

Answer 2

Answer:

$cos(x) = \frac{12}{13}$

$\frac{ - 119}{13}$

$1$

Step-by-step explanation:

AC = 10cm

AE = EC = 5cm

AD = CD = 13cm

(a)

$cos(x) = \frac{12}{13}$

(b)

${ \sin }^{2} x - { \cos }^{2} x = ( \sin x - \cos x)( \sin x + \cos x) = (\frac{5}{13} - \frac{12}{13} )(\frac{5}{13} + \frac{12}{13} ) = \frac{ - 7}{13} \times \frac{17}{13} = \frac{ - 119}{13}$

(c)

${ \sin }^{2} y + { \cos }^{2} y = \frac{ {6}^{2} }{ {10}^{2} } + \frac{ {8}^{2} }{ {10}^{2} } = \frac{36 + 64}{100} = \frac{100}{100} = 1$