Question

In the given figure , AD is a median of ∆ABC , BM and CN are perpendiculars drawn from B anf C respectively on AD and AD produced . Prove that BM = CN .​

Answer 1

thanks for the 5 points thank you

Answer 2

Answer:

AD is a median of BC

∴ BD=CD

In ∆CND and ∆BMD

∠CND=∠BMD (both 90°)

∠CDN=∠MDB (Vertically opposite angles)

CD=BD (proved above)

By AAS rule of congurency...

∆CND ≡ ∆BMD

∴BM=CN

Hence Proved