In the given figure , AD is a median of ∆ABC , BM and CN are perpendiculars drawn from B anf C respectively on AD and AD produced . Prove that BM = CN .
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Answer:
AD is a median of BC
∴ BD=CD
In ∆CND and ∆BMD
∠CND=∠BMD (both 90°)
∠CDN=∠MDB (Vertically opposite angles)
CD=BD (proved above)
By AAS rule of congurency...
∆CND ≡ ∆BMD
∴BM=CN
Hence Proved
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