Question

In the given figure, AD is median and ∠ B = 350 and AB = AC then find the value of ∠BAD​

Answer 1

Step-by-step explanation:

Given information:

AD is median,

AB=AC,

/_ABC or /_B =35°.

In triangle ABC, two sides of triangle are equal. It means triangle ABC is an isosceles triangle.

/_ADB=/_ADC=90° (AD is median)

In ∆ABD we have,

/_BAD + /_ABD =90°

/_BAD =90° - 35°

/_BAD = 55°

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Answer 2

Given:-

• AD is the median from vertex A to side BC
• ∠ABC = 35°
• AB = AC

To find:-

• Value of ∠BAD

Answer:-

As AB = AC, it means that △ABC is an isosceles triangle.

In △ADB and △ADC,

• AD = AD (Common)
• BD = CD. (AD is median)
• AB = AC (Given)

So, △ADB ≅ △ADC (SSS)

Hence, ∠ADB = ∠ADC ----( 1 ) (CPCTC)

Now,

BC is a line segment

∠ADB + ∠ADC = 180° (linear pair)

→ ∠ADB + ∠ADB = 180° [From ( 1 )]

→ 2∠ADB = 180°

→ ∠ADB = ∠ADC = 90° ----( 2 )

In △ADB,

• ∠ADB = 90° [From ( 2 )]
• ∠ABD = 35° [Given]
• ∠BAD = ?

We know that, in a triangle total angle is 180°

So,

∠ADB + ∠ABD + ∠BAD = 180°

→ 90° + 35° + ∠BAD = 180°

→ 125° + ∠BAD = 180°

→ ∠BAD = 180° - 125°

→ ∠BAD = 55° Ans.