Question

in the given figure AD is perpendicular to BC, AE is the angle bisector of BAC. Find DAE

Answer 1

ln ABC,
60°+35°+LBAC=180
LBAC=180-95
LBAC=85°
AE is the angle bisector of LBAC
=> LBAE + LEAC=LBAC
2LBAE=85
LBAE=42.5
In BAE,
60+42.5+LBEA=180
LBEA=180-102.5
LBEA=77.5
In ADE,
90+77.5+LDAE=180
LDAE=180-90-77.5
LDAE=90-77.5
LDAE=12.5 If u like this one pls mark it as the brainliest...

Answer 2

Answer:

ln ABC,

60°+35°+LBAC=180

LBAC=180-95

LBAC=85°

AE is the angle bisector of LBAC

=> LBAE + LEAC=LBAC

2LBAE=85

LBAE=42.5

In BAE,

60+42.5+LBEA=180

LBEA=180-102.5

LBEA=77.5

In ADE,

90+77.5+LDAE=180

LDAE=180-90-77.5

LDAE=90-77.5

LDAE=12.5 If u like this one pls mark it as the brainliest...

Step-by-step explanation: