Question

in the given figure ad is perpendicular to BC prove that a b square + cd square is equal to BD square + ac square
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Answer 1

Answer:

AB² + CD² = AC² + BD²

Step-by-step explanation:

Applying Pythagoras theorem to right triangles, ABD & ACD,

AB² = AD² + BD² ------ (1)

AC² = AD² + CD² ------ (2)

ii) Subtraction (2) from (1):

AB² - AC² = BD² - CD²

Rearranging, AB² + CD² = AC² + BD² [Proved]

Hope this helps :)