in the given figure AD is the bisector of angle A of triangle ABC in which ab is equal to AC prove that angles opposite to equal sides are equal
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Proved below.
Step-by-step explanation:
Given:
Here AD is the bisector of angle A of triangle ABC.
Also AB = AC
To prove:
∠ ABD = ∠ ACD
Proof:
Now, in ΔBAD and ΔCAD
AD = AD [common]
AB = AC [Given]
∠ BAD = ∠ CAD [given AD bisects ∠ BAC]
ΔBAD ≅ ΔCAD [By SAS test of congruence]
∴ ∠ ABD = ∠ ACD [By CPCT]
Therefore, angles opposite to equal sides are equal.
Hence Proved.
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