In the given figure AD is the bisector of ∠BAC, and AB = AC
By which criteria ∆ADB ≅ ∆ADC
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Answer:
Given : AD is the perpendicular
bisector of BC,AB=AC
To show △ADB≅△ADC
proof :- In △ADB and△ADC
AD=AD (common)
∠ADB=∠ADC
BD=CD (AD is perpendicular bisector)
∴△ADB≅△ ADC by SAS congruence .
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