Question

In the given figure, AD is the median and DE II AB. Prove that BE is the median.​

Answer 1

Answer:

Since AD is the median of ΔABC, then BD = DC.

Given, DE || AB and DE is drawn from the mid point of BC i.e.D, then by converse of mid-point theorem,

it bisects the third side which in this case is AC at E.

Therefore, E is the mid point of AC.

Hence, BE is the median of ΔABC.

Step-by-step explanation:

Answer 2

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Since AD is the median of ΔABC, then BD = DC.

Given, DE || AB and DE is drawn from the mid point of BC i.e.D, then by converse of mid-point theorem,

it bisects the third side which in this case is AC at E.

Therefore, E is the mid point of AC.

Hence, BE is the median of ΔABC.

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