Question

in the given figure ad is the median of triangle abc is produced to m .if bm and cm are perpendiculardrawn on ad and ad produced prove bl =cm

Answer 1

in ΔBDL and ΔCDM,

∠BLD=∠CMD(both equal to 90°)

∠BDL=∠CDM(vetically opposite angles are equal)

BD=CD(AD is median)

∴ΔBDL ≡ ΔCDM (AAS conguency)

⇒BL=CM (cpct,corresponding parts of congruent triangles)

hence proved

I AM IN CLASS 7

Answer 2

${\huge \underline{\mathfrak\green{hy \:mate}}}$

${\huge{\bf\red{answer :}}}$

in ΔBDL and ΔCDM,

∠BLD=∠CMD(both equal to 90°)

∠BDL=∠CDM(vetically opposite angles are equal)

BD=CD(AD is median)

∴ΔBDL ≡ ΔCDM (AAS conguency)

⇒BL=CM (cpct,corresponding parts of congruent triangles)

hence proved

${\huge{\bf\red{Thanks,}}}$

I hope it's helpful